Will somebody help explain some math problems to me? I will give a medal and become a fan.
start posting the questions you need help with
ok
Here is my first question thank you 7. What is the slope of the line that passes through the pair of points (2, 5) and (8, 3)? (1 point) 1/3 -1/3 3 –3
The slope of the line through points (x1,y1) and (x2,y2) is given by : \(\huge m=\frac{y_1-y_2}{x_1-x_2}\) now,just put the values and find m.
ok thank you i will solve it right now
Is it negative 1/3?
YES! good work :)
thank you
here is the next question 11. Write an equation in point-slope form for the line through the given point with the given slope. (5, 2); m = 3 (1 point) y + 2 = 3(x – 5) y + 2 = 3x – 5 y – 2 = 3(x + 5) y – 2 = 3(x – 5)
slope point form : \(\large y-y_1 = m (x-x_1)\) where point is x1,y1 = 5, 2 here
so would it be a? this one is a little harder
'a' has y+2 but according to the formula, left side = y-y1 with y1 = 2 so left side = y-2
so d?
\(\Large \checkmark \)
thank you again. do you mind helping me on a couple more i am doing a unit test? :)
18. Write an equation for the line that is parallel to the given line and passes through the given point. y = 3x + 7; (2, 10) (1 point) y = 3x + 11 y = 3x + 4 y = –3x + 4 y = ( )x + 4
i just realized i for got to separate them 18. Write an equation for the line that is parallel to the given line and passes through the given point. y = 3x + 7; (2, 10) (1 point) y = 3x + 11 y = 3x + 4 y = –3x + 4 y = (-1/3 )x + 4
parallel lines have same slope! so, first do u know how to find slope of y = 3x +7 ?
Not really :(
compare y= 3x+7 with y= mx+c then m= slope
\(\large \bf y= \color{red}{3}x+7\\ y= \color{red}{m}x+c \)
so would the answer be b?
YES! good :)
20. Tell whether the lines for each pair of equations are parallel, perpendicular, or neither. y = ( )x + 8 –2x + 8y = 4 (1 point) parallel perpendicular neither
whats in the bracket ?? "()"
oh -1/4
ok,so comparing y = (-1/4)x + 8 with y= mx+c , we get slope of 1st line as m = -1/4
to get the slope of 2nd line, we will have to isolate 'y' from –2x + 8y = 4 can you try ? start by adding 2x on both sides
Would it be perpendicular ?
nopes. –2x + 8y = 4 add 2x on both sides, what u get ?
-2x +2x +8y = 4 + 2x so, 0 +8y = 2x+4 8y = 2x+4 now divide by 8 on both sides
y=1/4x+1/2
correct, so comparing that with y=mx+c we get slope = m' = +1/4 so they are neither parallel, nor perpendicular :)
Ok thank you I will see if i need more help 1 sec
sure :)
21. Write the equation of a line that is perpendicular to the given line and that passes through the given point. y – 2 =7/3 (x + 5); (–4, 9) (1 point) y – 9 = (-3)/7 (x – 4) y – 9 =3/7 (x – 4) y – 9 = (-3)/7 (x + 4) y – 9 =3/7 (x + 4) the (-3)/7 means that it is negative 3 over 7
y – 2 =7/3 (x + 5) means the slope of this line is m' = 7/3 the slope of perpendicular line will be m =-1/m' = -3/7 and you have the point x1,y1 =-4,9 use the same formula again, \(y-y_1 =m (x-x_1)\)
would it be c?
\(\huge \checkmark \quad \ddot \smile \)
oh good i got another one right yay :)
yaay, congrats :)
I want to thank everybody for the great help Thank you :)
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