Question

An initial population of 745 quail increases at an annual rate of 16%. Write an exponential function to model the quail population. What will the approximate population be after 4 years?

Answer 1

@agent0smith can you help plzzzz?:( i have to hurry and get this done D:

Answer 2

A = P (1 + r)^t

solve

Answer 3

hmmm im not really sure, but ill try A=P1^t+Pr^t ?? @sourwing

Answer 4

@jdoe0001 please hellpppp

Answer 5

Ok, so the formula for exponential is
y=a(1+r)^x

Answer 6

Where a=initial amount
R=rate
And x=time

Answer 7

\[\Large A = P (1 + r)^t\]
so r = 0.16, P = 745\[\LARGE A = 745 (1+0.16)^t\]

Do things in brackets FIRST. Not as you did above.

Answer 8

And t=4^

Answer 9

so would it be A=745(1.16)^t

Answer 10

A = P (1 + r)^t

A=P1^t+Pr^t

DO NOT DO THIS. You cannot distribute when there's an exponent, that's not following order of operations.

Answer 11

Yes, that's correct. And t=4
So ur next step would be 1.26^4

Answer 12

1.16*

Answer 13

According to PEMdAS

Answer 14

so would it be A=1348.92??

Answer 15

as the final answer?

Answer 16

Yes

Answer 17

ok so that would be the approximate population after 4 years? so the exponential function would be A=745(1.16)^t ???

Answer 18

Yup

Answer 19

what is the exact population? because you can't have a decimal for people lol

Answer 20

I guess u can round up to 1349

Answer 21

Round up or down, it's an approximation so either is fine. Round up is usually better for real things.

Answer 22

or just say ~1350

Answer 23

"what is the exact population?" note the question doesn't ask for exact population.

Answer 24

ok! and is the exponential function that i wrote up above correct?

Answer 25

Yes, it is correct

Answer 26

are you positive?(:

Answer 27

lol I gave you a medal in the other question because it was correct!

Answer 28

ok thanks guyssss! (: