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Geometry 8 Online
OpenStudy (anonymous):

Sorry, guys. Just want to make sure I don't get a bad grade! Is this correct? center ( 7, -3), radius = sqrt 7 @nikato @AdrDiazEs

OpenStudy (anonymous):

OpenStudy (anonymous):

NO THIS IS THE ANSWER ----> (x-7)^2 + (y+3)^2 = 7

OpenStudy (anonymous):

Don't write the X twice, the first is x, the second is Y :) and sqrt 7 squared is 7 .. that's why :)

OpenStudy (nikato):

Yea, sqrt 7 x sqrt 7= 7 not 49

OpenStudy (anonymous):

Oops, I didn't mean to and ahh I forgot to square the second section. Thank you!

OpenStudy (anonymous):

Hope I'm not bothering you guys, if I am just let me know. How do I do this one? @AdrDiazEs @nikato

OpenStudy (jdoe0001):

look at the picture... what do you think?

OpenStudy (anonymous):

I have no idea :x

OpenStudy (nikato):

Just use the same formula

OpenStudy (anonymous):

x^2 + (y-8)^2 = 64

OpenStudy (nikato):

(X-0)^2 is simply x^2 when simplified

OpenStudy (anonymous):

This is the formula (h;k) r=radium (x-h)^2 + (y-k)^2 = r^2

OpenStudy (jdoe0001):

\( \begin{array}{llll} center\qquad (&0,&8)\qquad radius &8\\ &h&k&r \end{array}\implies \begin{array}{llll} (x-h)^2+(y-k)^2=r^2\\ \quad \\ (x-(0))^2+(y-(8))^2=(8)^2 \end{array}\)

OpenStudy (anonymous):

Ohh I see. But I don't have the ^ symbol or the space, do I just put \[x ^{2}+(y-8)^{2}=64?\]

OpenStudy (jdoe0001):

I think you're meant to use ^ from the keyboard

OpenStudy (anonymous):

It's drag and drop, my choices are at the bottom in the pic :x

OpenStudy (anonymous):

@AdrDiazEs

OpenStudy (anonymous):

YES! that's right :)

OpenStudy (anonymous):

Okay, do you mind showing me how to complete this? Find the coordinates for the center for this circle. (x + 3)² + (y - 5)² = 25

OpenStudy (nikato):

center is (-3,5)

OpenStudy (nikato):

rememeber that formula

OpenStudy (anonymous):

The center is (-3;5) :)

OpenStudy (anonymous):

Okay, but how do I figure that out

OpenStudy (anonymous):

because those are the numbers H and K that you used before... remember?

OpenStudy (anonymous):

I just do the formula backwards? Lol

OpenStudy (nikato):

find what was pluggged in for h and k

OpenStudy (anonymous):

Oh, I see. Thanks again!

OpenStudy (anonymous):

You can replace values of X and Y ... and try to figure out by making your own graph. :)

OpenStudy (anonymous):

What about Find the length of the radius for this circle. (x - 3)² + (y - 5)² = 8 my choices are 4, 8, and \[2\sqrt{2}\] I think it is \[2\sqrt{2}\] is that right?

OpenStudy (nikato):

yup remeber in the formula it was r^2

OpenStudy (anonymous):

That's what I thought :) Thanks!

OpenStudy (nikato):

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