Sorry, guys. Just want to make sure I don't get a bad grade! Is this correct? center ( 7, -3), radius = sqrt 7 @nikato @AdrDiazEs
NO THIS IS THE ANSWER ----> (x-7)^2 + (y+3)^2 = 7
Don't write the X twice, the first is x, the second is Y :) and sqrt 7 squared is 7 .. that's why :)
Yea, sqrt 7 x sqrt 7= 7 not 49
Oops, I didn't mean to and ahh I forgot to square the second section. Thank you!
Hope I'm not bothering you guys, if I am just let me know. How do I do this one? @AdrDiazEs @nikato
look at the picture... what do you think?
I have no idea :x
Just use the same formula
x^2 + (y-8)^2 = 64
(X-0)^2 is simply x^2 when simplified
This is the formula (h;k) r=radium (x-h)^2 + (y-k)^2 = r^2
\( \begin{array}{llll} center\qquad (&0,&8)\qquad radius &8\\ &h&k&r \end{array}\implies \begin{array}{llll} (x-h)^2+(y-k)^2=r^2\\ \quad \\ (x-(0))^2+(y-(8))^2=(8)^2 \end{array}\)
Ohh I see. But I don't have the ^ symbol or the space, do I just put \[x ^{2}+(y-8)^{2}=64?\]
I think you're meant to use ^ from the keyboard
It's drag and drop, my choices are at the bottom in the pic :x
@AdrDiazEs
YES! that's right :)
Okay, do you mind showing me how to complete this? Find the coordinates for the center for this circle. (x + 3)² + (y - 5)² = 25
center is (-3,5)
rememeber that formula
The center is (-3;5) :)
Okay, but how do I figure that out
because those are the numbers H and K that you used before... remember?
I just do the formula backwards? Lol
find what was pluggged in for h and k
Oh, I see. Thanks again!
You can replace values of X and Y ... and try to figure out by making your own graph. :)
What about Find the length of the radius for this circle. (x - 3)² + (y - 5)² = 8 my choices are 4, 8, and \[2\sqrt{2}\] I think it is \[2\sqrt{2}\] is that right?
yup remeber in the formula it was r^2
That's what I thought :) Thanks!
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