Question

if f(x)=1/3x-1 and g(x) = f^-1(x), find g’(x).

Answer 1

we literally just did this?

Answer 2

g o f) (x) = 2 ( 3x^2 - 1) = 6x^2 - 2

two:
An = 5 * 2^n

three
can't do with text

Answer 3

Thats incorrect darling

Answer 4

Don't patronize her

Answer 5

Please reference this question
http://openstudy.com/study#/updates/52c33e98e4b0b729fb8c0a95

Answer 6

is it \[f(x)=\frac{1}{3x-1}\]??

Answer 7

whoops

Answer 8

@satellite73 yes

Answer 9

one method is to actually find the inverse, and then take the derivative of that

Answer 10

not too hard to find
\[x=\frac{1}{3y-1}\]
\[3y-1=\frac{1}{x}\]
\[3y=\frac{1}{x}+1\]
\[y=\frac{1}{3x}+\frac{1}{3}\] or
\[f^{-1}(x)=\frac{1}{3x}+\frac{1}{3}\] now the derivative is easy to find

Answer 11

i mean i guess it is easy to find, right?

Answer 12

1/3

Answer 13

oh heck no

Answer 14

grrrr

Answer 15

the derivative of \(\frac{1}{x}\) is \(-\frac{1}{x^2}\)

Answer 16

so the derivative of \(\frac{1}{3}\) is \(-\frac{1}{3x^2}\)

Answer 17

oops typo there, i mean the derivative of
\[\frac{1}{3x}\] is
\[-\frac{1}{3x^2}\]