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OpenStudy (anonymous):
Please help simplifying complete
5+(x+3/x−1)/ (3x−1/1−x^2)
the answer is -2(1+x) from key. Please show details on how to solve thank you.
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OpenStudy (anonymous):
\[ \large 5+\frac{x+3}{x-1} \div \frac{3x-1}{1-x^2}\]
OpenStudy (anonymous):
Is that is?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
\[ 5+\frac{x+3}{x-1} * \frac{1-x^2}{3x-1}\]
OpenStudy (anonymous):
\(1-x^2=-(x-1)(x+1)\)
ummm are you sure I wrote out the equation correctly???
Can you write it out?
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OpenStudy (anonymous):
Yes I did, but the answer key may be wrong.
OpenStudy (anonymous):
5+(x+3/x-1)/(3x-1/1-x^2)
OpenStudy (bibby):
you're doing it right, yeah. the x-1's cancel
OpenStudy (shamil98):
you have to add 5 to the fraction first, then divide :P
\[\huge (5 + \frac{ x+3 }{ x-1 } )\div \frac{ 3x-1 }{ 1-x^2 }\]
\[\huge \frac{ 2(3x-1) }{ x-1 } * \frac{ -(x+1)(x-1) }{ 3x-1 }\]
\[\huge \frac{ 2\cancel{(3x-1)} }{ \cancel{x-1} } * \frac{ -(x+1)\cancel{(x-1)} }{ \cancel{3x-1} }\]
OpenStudy (shamil98):
\[\huge -2(x+1)\]
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OpenStudy (anonymous):
Thank you Shamil98
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