The generation time G for a particular bacteria is the time it takes for the population to double. The bacteria increase in population is shown by the formula G= (t)/(3.3log(base a)P) where t is the time period of the population increase, a is the number of bacteria at the beginning of the time period, and P is the number of bacteria at the end of the time period. If the generation time for the bacteria is 4.5 hours, how long will it take 4 of these bacteria to multiply into a colony of 7,525 bacteria? Round to the nearest hour.
That's a complicated description of 7525 = 4*[2^(t/G)] solve this by taking logarithms of both sides, finding t.
lol tell me about it! do ya mind walking me through it? i have no idea what I'm doing lol
@RadEn could you help please?
is it 95 hours?
don't worry about it anymore
When things double in each of n steps, you have the factor 2 being applied n times: so that in three doubling times, you have A go to A*2*2*2= A*2^3 = 8 A. I used t/G to determine how many doubling times (and this could be a decimal number, then got 4 * 2^(t/G) = 7525 take logarithms log 4 + (t/G) log 2 = log (7525) = 3.877 (t/G) = [3.877 - log 4]/(log 2) = (3.877 - 0.602)/(0.301) t/G = 10.88 t = 48.96, if I haven't made any calculation mistakes Quick check: 2^11 = 2048 and 4*2048=8192, which is close to your 7525. Exact check: 2^10.88 = 1884.5 and that x 4 = 7538, almost exactly matched.
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