Find the slope of a line parallel to the line through the given points. P(-2, 4), Q(6, -2) @nikato I got 4/3. Is this right?
I did \[\frac{ y2-y1 }{ x2-x1 } \] and got \[\frac{ -6 }{ 8 }\] simplified to \[\frac{ -3 }{ 4}\] parallel would be \[\frac{ 4 }{ 3 }\] right?
No, if 2 lines are parallel, they would have the same slope
S it'll be just -3/4
http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut28parallel.gif
4/3 would be the slope of the line perpendicular to it
but.... parallel is being an equal distance apart everywhere
But ur just finding the slope, right?
yes
Yes, and u found that it was -3/4 and the line parallel to that line would have the same slope, so that line also has a slope of -3/4
Oh, okay. Thank you!
Yea, no problem. Are u sure u understand it now?
I think I'm just a bit confused on what the slope actually is :T
I mean parallel means they don't touch, I don't understand how they could have the same anything
Slope is kinda like how much the line slants, like its steepness
Yes, parallel means they never touch. And in order for that to happen, they must have the same "steepness"
Oh, now I see. But perpendicular would have opposite slopes, right?
reciprocal with opposite sign would be for perpendicular
...what?
It would be the opposite slope right? e.g. -1/3 and 1/3
oops I meant -3/-1 and 1/3
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