Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.

Question

anonymous · Answer

@hartnn

anonymous · Answer

This is the farthest I have gotten in this equation 
F=$$F=150(\cos(30),\sin(30))+75(\cos150),\sin(150)$$

anonymous · Answer

and then this,
$$F=150(\sqrt{3}/2,1/2)+75(-\sqrt{3}/2,1/2)$$

loser66 · Answer

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loser66 · Answer

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anonymous · Answer

Okay, so it looks like you can use Pythagorean Theorem in this question

anonymous · Answer

if we know another side, but my equation that I have are they correct?

loser66 · Answer

F = F1 + F2 
and we have to separate them into 2 dimensions x and y
to x direction, F_x = F1_x + F2_x = F1cos 30 + F2 cos 30
to y direction F_y = F1_y + F2_y = F1sin30 + F2 sin (60)
 and then F = $\sqrt{Fx^2 +F_y^2}$

anonymous · Answer

$$F1= 150\cos(30)+150\sin(30)$$
$$F2=75\cos(150)+75\sin(150)$$

anonymous · Answer

Like that?

anonymous · Answer

@ganeshie8 Do you have any ideas of helping me solve this equation?

loser66 · Answer

right people !! @ganeshie8  hihihii

ganeshie8 · Answer

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