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Chemistry 13 Online
OpenStudy (anonymous):

Given 4.8 moles of a gas in a 1.8 L container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.) Answer 6.79 torr 66.55 torr 6.79 x 100 atm 6.66 x 101 atm

OpenStudy (anonymous):

When calculating, I got 66.58... Should I multiply that by 10^-1 to get the fourth answer or is the answer 66.55 torr?

OpenStudy (anonymous):

@abb0t @Preetha

OpenStudy (abb0t):

Use the ideal gas law formula: \(\sf \color{red}{PV = nRT}\) where P = pressure V = volume n = mole R = gas constant T = temperature Since you want to find \(\sf \color{green}{P}\), you need to rearrange the formula around, meaning divide by volume.

OpenStudy (anonymous):

Like I said, I calculated and got 66.58~, do I then multiply that by 10^-1 to get 6.66 * 10^1 atm?

OpenStudy (anonymous):

@abb0t

OpenStudy (abb0t):

I do not have a calculator with me, but if you followed what I did, you should be correct.

OpenStudy (anonymous):

Okay, thanks.

OpenStudy (preetha):

Check your units. If you use the given R as a constant, the P should be in atm. T should be in K (Celsius+273.15). And then it is math.

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