Given 4.8 moles of a gas in a 1.8 L container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.) Answer 6.79 torr 66.55 torr 6.79 x 100 atm 6.66 x 101 atm
When calculating, I got 66.58... Should I multiply that by 10^-1 to get the fourth answer or is the answer 66.55 torr?
@abb0t @Preetha
Use the ideal gas law formula: \(\sf \color{red}{PV = nRT}\) where P = pressure V = volume n = mole R = gas constant T = temperature Since you want to find \(\sf \color{green}{P}\), you need to rearrange the formula around, meaning divide by volume.
Like I said, I calculated and got 66.58~, do I then multiply that by 10^-1 to get 6.66 * 10^1 atm?
@abb0t
I do not have a calculator with me, but if you followed what I did, you should be correct.
Okay, thanks.
Check your units. If you use the given R as a constant, the P should be in atm. T should be in K (Celsius+273.15). And then it is math.
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