Question

Select the inequality that models the problem.

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

A.
2w • w < 50

B.
2w < 50

C.
2 + 2w < 50

D.
2 • 2w + 2w < 50

Answer 1

\(\Huge{\color{purple}{\textbf{W}} \color{orange}{\cal{E}} \color{green}{\mathbb{L}} \color{blue}{\mathsf{C}} \color{maroon}{\rm{O}} \color{red}{\tt{M}} \color{gold}{\tt{E}} \space \color{orchid}{\mathbf{T}} \color{Navy}{\mathsf{O}} \space \color{OrangeRed}{\boldsymbol{O}} \color{Olive}{\mathbf{P}} \color{Lime}{\textbf{E}} \color{DarkOrchid}{\mathsf{N}} \color{Tan}{\mathtt{S}} \color{magenta}{\mathbb{T}} \color{goldenrod}{\mathsf{U}} \color{ForestGreen}{\textbf{D}} \color{Salmon}{\mathsf{Y}} \ddot \smile }\)
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So, we would have 2w * w < 50

We multiply by two, because the length is twice the width.
We then multiply all that by the width.

It is less than 50, so we use a less-than symbol.



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Answer 2

@compassionate thank you can you help me with one more