Use the Change of Base Formula to evaluate log877.
Do you mean \( \log_{10} 877\) or \( \log_8 77\) or \(\log_{87} 7\), or maybe something else?
\(\log_ba = \dfrac{\log_c a}{\log_c b}\)
i ment log (base 8)77
Since you have \( \log_8 77\), use the change of base formula above with a = 77, b = 8, c = 10
ok i did that and i think i got that wrong cos i got 69.53 =9.62
Using the change of base formula, you should get this. Now just use a calculator to find the logs of 77 and 8 and divide. \(\log_8 77 = \dfrac{\log_{10} 77}{\log_{10} 8}\)
i did that D: and log (base 10)77 is coming up as just 77 on my calculator and log (base 10)8 is coming up as just 8 and then i divide the two i get 9.62.
I don't think you're using your calculator correctly. With my calculator I get these results \( \log_{10} 77 = 1.88649\) \( \log_{10} 8 = 0.90309\)
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