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Mathematics 6 Online
OpenStudy (tester97):

Use the Change of Base Formula to evaluate log877.

OpenStudy (mathstudent55):

Do you mean \( \log_{10} 877\) or \( \log_8 77\) or \(\log_{87} 7\), or maybe something else?

OpenStudy (mathstudent55):

\(\log_ba = \dfrac{\log_c a}{\log_c b}\)

OpenStudy (tester97):

i ment log (base 8)77

OpenStudy (mathstudent55):

Since you have \( \log_8 77\), use the change of base formula above with a = 77, b = 8, c = 10

OpenStudy (tester97):

ok i did that and i think i got that wrong cos i got 69.53 =9.62

OpenStudy (mathstudent55):

Using the change of base formula, you should get this. Now just use a calculator to find the logs of 77 and 8 and divide. \(\log_8 77 = \dfrac{\log_{10} 77}{\log_{10} 8}\)

OpenStudy (tester97):

i did that D: and log (base 10)77 is coming up as just 77 on my calculator and log (base 10)8 is coming up as just 8 and then i divide the two i get 9.62.

OpenStudy (mathstudent55):

I don't think you're using your calculator correctly. With my calculator I get these results \( \log_{10} 77 = 1.88649\) \( \log_{10} 8 = 0.90309\)

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