Question

Does anybody know the value of log3(27)

Answer 1

Do you know the definition of log?

Answer 2

oh uh no

Answer 3

Here it is:

\( \log_b x = y \iff b^y = x\)

Answer 4

More important is how to obtain that value. One way in which you could do this, probably the easiest way, would be to re-write that 27 as 3^3. Then use the property that y=log3 x and y=3^x are INVERSE FUNCTIONS.

Answer 5

Now using the definition of log, use the values you have for b, x, and y to change the log you are given to the exponential expression to the right.

Answer 6

\(\log_b x = y \iff b^y = x\)

\(\log_3 27 = y \iff 3^y = 27\)

3 to what power equals 27?

Answer 7

oh wow, ok thanks

Answer 8

You're welcome.

Answer 9

\[\log_{3} 27=\log_{3} 3^{3}=3\log_{3} 3=3*1=3\]
\[\log_{a} a=1\]