Question

Solve using natural logarithms:
\[3e^{2x}+ 5 = 27 \]
Minus five from each side:
\[3e^{2x} = 22 \]
Divide each side by three:
\[e^{2x} = 7.3333\]
Now what? I forgot :O

Answer 1

I think we use ln to cancel the 3?
2x = 1.992430164690206162083930
Divide each side by two:
x = 0.9962150823451030810419650

Answer 2

Possibly? I'm not sure :/

Answer 3

e^2x = 22/3
ln both sides, ln e ^ 2x = ln (22/3) --> 2x = ln (22/3)
x = (ln(22/3))/2

Answer 4

exactly what you got, hihihi = 0.996

Answer 5

Thanks :)