Differentiate:

Question

Differentiate:

luigi0210 · Answer

$$\LARGE y=\frac{4x^3-7x}{5x^2+2}$$

anonymous · Answer

quotient rule

luigi0210 · Answer

If I'm not mistaken you use quotient rule right?
So: $$\LARGE y'=\frac{(5x^2+2)(4x^3-7x)'-(5x^2+2)'(4x^3-7x)}{(5x^2+2)^2}$$

anonymous · Answer

$$\huge\frac{ f(x)g'(x)-g(x)f'(x) }{f(x)^2}$$

freethinker · Answer

you can also use product rule, which implements another rule

anonymous · Answer

implicit differentiation 
dy/dx   y'=20x^4++59x^2-14/(5x^2+2)^2

freethinker · Answer

y' = 4x^3 - 7x * (5x^2 + 2)^(-1)

freethinker · Answer

whichever you are most comfortable with
you can even differentiate using the definition

shamil98 · Answer

u already know how to do dis

luigi0210 · Answer

Thanks guys
@shamil98 Shh xD

luigi0210 · Answer

I'm curious as to the implicit differentiation approach tho.

freethinker · Answer

just like the other rules or ways of solving it, it would not be optimal to do so 
besides, implicit differentiation just means you are waiting for the value of the unknown, which in this case is the x 
y = x^2
y' = 2x * x'

anonymous · Answer

$5x^2y+2y-4x^3+7x=0$ now use implicit

luigi0210 · Answer

Oh, now I see.