Why the displacement current I_D is always zero in an open surface that is perpendicular to a straight wire whose radius is a?
Displacement current only comes into picture, when there is a changing electric flux!
Don't think so!
it is.. you see.. when a capacitor is charging, electric field is increasing and hence there is a changing electric flux.. which gives rise to a magnetic field.. just like how changing magnetic flux, gives rise to an electric field!
Do we have a capacitor here in the example?? There is only a straight wire that contains a constant current I. I know quite the answer and want you to use the Gauss' law though.
exactly.. there is a constant current, due to a constant pd, due to a constant field, due to a constant flux, and hence no displacement current :P
Here's a better answer:|dw:1388665465230:dw|
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