Question

---NEED HELP!---
Henry can paddle his kayak in still water with a speed of 20m per minute. If Henry paddles 100m against the current in less time as he paddles 150m with the current. Find the speed of the current. Assume that at no time is he being swept away by the current.

Answer 1

@satellite73 @.Sam. @Callisto @amistre64 @myininaya @robtobey

Answer 2

Help please?

Answer 3

20+c downstream
20-c upstream
c=current
20m/min=rate of the kayak in still water

then
100(20+c)=150(20-c )
2000+100C=3000-150C

Answer 4

C=4

Answer 5

This is an inequality question @zpupster @MajicMuzyk.

Answer 6

@zpupster
I don't get this part 20+c downstream
20-c upstream
c=current

Answer 7

and the part after @zpupster

Answer 8

why did you multiply distance by speed?

Answer 9

Can you also answer this question: factorise 3x^2 - 40 + 50.

Answer 10

3x2+10
that is factored




for the other
20 + c- what the current is downstream + what he paddles in still H2O
and 20 -c the current upstream is neg,

Answer 11

part after goes like this
2000+100C=3000-150C add 150c to both sides and subtract 2000
250c = 1000 divide both sides by 250

c=4 m/min

Answer 12

I forgot the x sorry 3x^2-40x+50

Answer 13

but the answer is o<c<4???

Answer 14

m/min

Answer 15

Why did you multiply here? 100(20+c)=150(20-c )