Question

can you do this please:
\[\int\limits_{-1}^{0}3x \sqrt{1-3x} dx \]
by using the substitution u^2=1-3x

Answer 1

u = 1 - 3x ------> x = (1-u)/3
du = -3 dx

Answer 2

yeah I know that, but then how you can deal with the limits
0 and -1

Answer 3

see the integral becomes :

Answer 4

can you evaluate that integration without the limits, first ?

Answer 5

yeah, yeah.. thanks a lot man

Answer 6

welcome :)