Solve. 3 + d < 3 – d A. d > –3 B. d < 6 C. d < 0 D. d < –6
Your answer would be C
e.e
Actually your answer would not be C
are you absolutely 200% positive cuz that's what I thought it was but I'm not quite sure...
3 + d < 3-d d< -1d
Divide -1 to each side. When you do that, the sign changes d is greater than.
well, then. Thanks @KirbyLegs
so A?
My Bad XD C is correct. This is how:
Aw haha :)
3 + d < 3 -d Add +d to each side 3+ 2d < 3
Aw thanks :)
Subtract 3 from each side 2d < 0 d < 0/2 d < 0 Sorry about that
In order to solve this linear inequality, we need to group all the variable terms on one side, and all the constant terms on the other side of the inequality. In our example, - term -d, will be moved to the left side. Notice that a term changes sign when it 'moves' from one side of the inequality to the other. In order to isolate the variable in this linear inequality, we need to get rid of the coefficient that multiplies it. This can be accomplished if both sides are divided by 2. We need to reduce this fraction to the lowest terms. This can be done by dividing out those factors that appear both in the numerator and in the denominator. In our example, this is the common factor: 2.
@MajicMuzyk honestly, I love you for writing something so long just for me to understand xD
Thank you :D I am glad that I could help!
:D
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