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Find the integral of (x-4)/x^2 dx from 1 to 2. (Answer: ln(2)-2.) ( I got 1/x-4/x^2 and should I integrate that from 1 to 2?)
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yes, do that integrate 1/x - 4/x^2 first :)
But I have trouble integrating those.
integral of 1/x is standard formula \(\int \dfrac{1}{x}dx = \ln x + c\) for 4/x^2 , 1/x^2 = x^-2 and so you can use the x^n formula
Thanks. I'll try that.
could you solve it ?
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Yes, I finally got it. Thank you so much. It worked.
most welcome ^_^
Thanks for the medal.
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