Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

For the graph shown, select the statement that best represents the given system of equations. 3y – x = 12 x – 3y = 6

OpenStudy (anonymous):

OpenStudy (anonymous):

A. coincident B. consistent and independent C. inconsistent D. not enough information

OpenStudy (anonymous):

@DSS UR HERE!!! :D

OpenStudy (anonymous):

Hey

OpenStudy (anonymous):

There is no solution to the system of equations as the lines are parallel. I'm not familiar with the vocabulary you have to choose from.

OpenStudy (anonymous):

not enough information?

OpenStudy (anonymous):

On the other hand, if there are NO points that work in both, then we say that the equations are INCONSISTENT. NO numbers that work in one are consistent with the other. When a system is "dependent," it means that ALL points that work in one of them ALSO work in the other one. Graphically, this means that one line is lying entirely on top of the other one, so that if you graphed both, you would really see only one line on the graph, since they are imposed on top of each other. One of them totally DEPENDS on the other one. When a system is "independent," it means that they are not lying on top of each other. There is EXACTLY ONE solution, and it is the point of intersection of the two lines. It's as if that one point is "independent" of the others. To sum up, a dependent system has INFINITELY MANY solutions. An independent system has EXACTLY ONE solution. From this information I would say inconsistent.

OpenStudy (anonymous):

Does that help?

OpenStudy (anonymous):

yes thx :D I have 3 more questions :D

OpenStudy (anonymous):

k

OpenStudy (anonymous):

For the graph shown, select the statement that best represents the given system of equations. 3y – x = 2 9y – 3x = 6

OpenStudy (anonymous):

OpenStudy (anonymous):

These are different equations for the same exact line...they share every point in common. They are consistent.

OpenStudy (anonymous):

and consistent and independed?

OpenStudy (anonymous):

No..independent only has one solution. this one has many...it would be dependent.

OpenStudy (anonymous):

A. not enough information B. coincident C. consistent and independent D. inconsistent

OpenStudy (anonymous):

I'd say it's just consistent.

OpenStudy (anonymous):

it doesn't have that as a choice @DSS

OpenStudy (anonymous):

Points that work in each equation...consistent. When a system is "dependent," it means that ALL points that work in one of them ALSO work in the other one. Graphically, this means that one line is lying entirely on top of the other one, so that if you graphed both, you would really see only one line on the graph, since they are imposed on top of each other. One of them totally DEPENDS on the other one. By the definitions given this is what I say. consistent & dependent

OpenStudy (anonymous):

Could it be not enough information because the appropriate choice isn't available?

OpenStudy (anonymous):

I think so

OpenStudy (anonymous):

For the graph shown, select the statement that best represents the given system of equations

OpenStudy (anonymous):

2y – 3x = 9 4y + 3x = 12 A. inconsistent B. consistent and independent C. coincident D. not enough information @DSS

OpenStudy (anonymous):

There is exactly one point that both equations share, (-2/3,7/2). I'd say consistent & independent.

OpenStudy (anonymous):

thx :D, last one

OpenStudy (anonymous):

What is the best approximation of the solution to the equations that these two lines represent? A. (0, 1) B. (1, 1) C. (1.5, 1) D. (1, 1.5)

OpenStudy (anonymous):

The two lines given...do you know how to determine the slope & y-intercept of each?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Give me the equations for both lines.

OpenStudy (anonymous):

c

OpenStudy (anonymous):

I think it's (1,1.5) find the x value first at 1, up 1.5

OpenStudy (anonymous):

ohhhh now I get it, thx :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!