Question

What is the solution to the equation 9^(x + 1) = 27 ?

Answer 1

x = 2.5

x = 0.5

x = –0.5

x = –3.5

Answer 2

takes logs on both sides
\[\log 9^{(x+1)}=\log 27\]
\[(x+1)\log9=\log 27\] move the power to the front
\[x+1=\frac{ \log27 }{ \log 9 }\] divide the like terms, logs
\[x+1=1.5\] subtract 1 to both sides
x=0.5

Answer 3

Thank You! I was really lost.

Answer 4

no problem :)

Answer 5

\(x+1=\dfrac{ \log27 }{ \log 9 } = \dfrac{\log 3^3}{\log 3^2} = \dfrac{3 \log 3}{2\log 3} = \dfrac{3}{2}=1.5\)

Answer 6

a good way of extending it hartnn :)