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Mathematics 9 Online
OpenStudy (anonymous):

HELP FOR A MEDAL AND FAN. :)

OpenStudy (anonymous):

Show all steps to simplify and solve each of the following rational expressions:

OpenStudy (anonymous):

OpenStudy (anonymous):

HI :D

OpenStudy (anonymous):

1. (2x+6)/(3x-1)+(x-5)/(3x-1) Factor out the GCF of 2 from each term in the polynomial. (2(x)+2(3))/(3x-1)+(x-5)/(3x-1) Factor out the GCF of 2 from 2x+6. (2(x+3))/(3x-1)+(x-5)/(3x-1) The numerators of expressions that have equal denominators can be combined. In this case, (2(x+3))/((3x-1)) and ((x-5))/((3x-1)) have the same denominator of (3x-1), so the numerators can be combined. (2(x+3)+(x-5))/(3x-1) Simplify the numerator of the expression. (2x+6+x-5)/(3x-1) Combine all similar terms in the polynomial 2x+6+x-5. (3x+1)/(3x-1)

OpenStudy (anonymous):

2. (3)/(y+4)-(2)/(y) Multiply each term by a factor of 1 that will equate all the denominators. In this case, all terms need a denominator of y(y+4). The (3)/((y+4)) expression needs to be multiplied by ((y))/((y)) to make the denominator y(y+4). The -(2)/(y) expression needs to be multiplied by ((y+4))/((y+4)) to make the denominator y(y+4). (3)/(y+4)*(y)/(y)-(2)/(y)*(y+4)/(y+4) Multiply the expression by a factor of 1 to create the least common denominator (LCD) of y(y+4). (3(y))/(y(y+4))-(2)/(y)*(y+4)/(y+4) Multiply the expression by a factor of 1 to create the least common denominator (LCD) of y(y+4). (3(y))/(y(y+4))-(2(y+4))/(y(y+4)) The numerators of expressions that have equal denominators can be combined. In this case, (3(y))/(y(y+4)) and -((2(y+4)))/(y(y+4)) have the same denominator of y(y+4), so the numerators can be combined. (3(y)-(2(y+4)))/(y(y+4)) Simplify the numerator of the expression. (3y-2y-8)/(y(y+4)) Since 3y and -2y are like terms, add -2y to 3y to get y. (y-8)/(y(y+4))

OpenStudy (anonymous):

3. (z^(2))/(z+4)-(16)/(z+4) Combine all similar expressions in the polynomial. (z^(2)-16)/(z+4) The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b). ((z-4)(z+4))/(z+4) Reduce the expression by canceling out the common factor of (z+4) from the numerator and denominator. ((z-4)<X>(z+4)<x>)/(<X>(z+4)<x>) Reduce the expression by canceling out the common factor of (z+4) from the numerator and denominator. (z-4) Remove the parentheses around the expression z-4. z-4

OpenStudy (anonymous):

do you understand it?

OpenStudy (anonymous):

Yes! thank you so much. c: i get it now!

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