Question

HELP FOR MEDAL AND FAN . :)

Answer 1

Its you change the language to Portuguese-Brazil?

Answer 2

For the first question:
\[\frac{ x-5 }{ 2x }+\frac{ x+1 }{ 2x }\]
In order to add the fractions, we have to use a property called "common denominator" wich says that if we can make the denominators equal, we can add the numerators as if they were only numbers, common denominator says:
\[\frac{ a }{ b }+\frac{ c }{ d }=\frac{ (ad+cb) }{ bd }\]
The mathematical expression of "common denominator" says that if I multiply the numerator and denominator by the denominator of the neighbor fraction, I can make a newer fraction wich represents the sum of the initial fractions.
Applying that to the problem:
\[\frac{ x-5 }{ 2x }+\frac{ x+1 }{ 2x }\]
The only multiplication to make them equal is multiplying by 1 since the denominators are already the same:
\[\frac{ (x-5+x+1) }{ 2x }\]
Using an algebraic property that allows me to add variables taking common factor and of course arithmetical definitions taht operates numbers, we end up with something like this:
\[\frac{ ((1+1)x-4) }{ 2x }\]
using the same arithmetical definitions for sum, we operate the interior of that parethesis and multiply by the variable:
\[\frac{ 2x-4 }{ 2x }\]
And that concludes the exercise.