Question

12 years ago

Answer 1

@jdoe0001
@JayDS
@jigglypuff314
@Loser66

Answer 2

In order to solve that, we have to recall some very very basic geomtry knowledge, in the circle there's two inscribed triangles, and we know that <DAB and <DCB are 90º (right angles), but the gave us the measure of the <BDC angle wich is 56º.
We know that a triangle's angles, sum up to 180º, and we know teo of the angles of the DCB triangle, so we can mathematically say:
\[180º=90º+56º+<CBD\]
and doing a little math:
\[<CBD= 180º-90º-56º=34º\]
so <CBD=36º.
We can see that <CAD and <CBD have the same arc, so they are equal.
so we deduce that <CAD=<CBD.
so <CAD=36º.
now, it's an inscribed angle, meaning that the angle it has, is twice the arc it encloses:
like this:
\[\alpha=\frac{ \theta }{ 2 }\]
where alpha plays the role of <CAD and theta the arc it encloses:
doing a little math:
arc<CAD= (36)(2) = 72º

Answer 3

Sorry I took so long, I'm a bit rusty when it comes to geometry.

Answer 4

thank you! but 72 isn't an option

Answer 5

@jigglypuff314 can u help?

Answer 6

What are the options?

Answer 7

Wait, did I just put 36 instead of 34?...