Question

divide the complex number :

Answer 1

\[\frac{ 4-2i }{ 3i}\]

Answer 2

multiply top and bottom either by \(i\) or \(-i\) your choice

Answer 3

how exactly is that done?

Answer 4

if you multiply by \(i\) you get as a first step
\[\frac{4i-2i^2}{3i^2}\] as a first steo, then, since \(i^2=-1\) it is
\[\frac{4i+2}{-3}\] as step 2
usually you skip the first step and go right to the second

Answer 5

then to put the complex number in standard from of \(a+bi\) you write it as
\[-\frac{2}{3}-\frac{4}{3}i\]

Answer 6

they have common denominators

Answer 7

yes, of course
that is because it started as
\[\frac{2+4i}{-3}\] but standard from is \(a+bi\) so you break it apart

Answer 8

so the next step is to simplify correct