Question

(-(2q^4)/7)^4

Answer 1

\(\left(-\dfrac{2q^4}{7}\right)^4\)
Looks like you need to raise each term/factor to the fourth power.
\(2^4 = 2 \times 2 \times 2 \times 2=16\)
Exponent rules tell you that \(x^{y^z}=x^{y \times z} = x^{yz}\) so \(q^{4^4}=q^{16}\)
\(7^4 = 7 \times 7 \times 7 \times 7=2401\)
An even number of negatives makes a positive, so
\(\dfrac{16q^{16}}{2401}\)