Find the angle between the given vectors to the nearest tenth of a degree. u = <8, 7>, v = <9, 7> @agent0smith
\[|u|~|v|~cos~\alpha=u\cdot v\] solve for alpha
a · b = |a| × |b| × cos(θ) Find a*b first, like in the last question.
so 8*9 and 7*7?
yes, and add the results
8*9 + 7*7 = |a| × |b| × cos(θ) find |a| and |b|, just use pythagoras to find their magnitudes
72+49=121
so from there what would i do>
find |a| and |b|, just use pythagoras to find their magnitudes
121 = |a| × |b| × cos(θ) All you need to do is find the magnitude of a and b, then find cosθ
For a vector w = <a, b> \[\Large |w| = \sqrt{a^2+b^2}\]ie use pythag basically.
i got like 87
For what?
u = <8, 7> Find |u| v = <9, 7> Find |v|
i feel so dumb
haha why?
i am so lost
If you had w = <4, 2> and need |w| \[\Large |w| = \sqrt{4^2+2^2} = \sqrt{20}\]
Find |u| and |v| in the same way.
u= \[\sqrt{113}\] v=\[\sqrt{130}\]
Good, so \[\Large 121 = \sqrt{113} \sqrt{130} × \cos(θ)\]now find cos(θ)
how lol
Could you do it if it was this?\[\Large 4 = 2 \times 3 \times \cos \theta\] If so, do the same thing!
Just get cosθ by itself.
so would it be 3.4 or something close to that
No, show me or tell me what you did.
i did sqrt of 113 timess sqrt of 130 then the answer i got i divided by 121
If you had 4=2×3×cosθ you would divide both sides by 6 right?
yes
So with \[\Large 121 = \sqrt{113} \sqrt{130} × \cos(θ)\]do the same thing... you might notice the mistake you made.
okay so when i i multiply the squre roots together i get 35.9, then i divided that by 121 and got 3.3 do i have to find the cos of that
If you had \[\Large 2 = 5 x\]you would divide both sides by 5 right? To get \[\Large \frac{ 2 }{ 5} = x\] You're doing things in the wrong order.
You're doing something weird with the square roots, actually... 35.9?? http://www.wolframalpha.com/input/?i=sqrt113+*+sqrt130
121=121.2*cos(θ)
Yes, now find the angle theta.
would i divide it now?
Yes, then find theta.
i got when i divided 0.9983498
0.9983498 = cosθ Find θ
Use a calculator and the inverse cosine button
Inverse cosine right!
holy poop please tell me is that haha i've been here trying to figure it out
i got 3.292 so rounded 3.3
Looks about right
YAY finally lololol THANK YOU SO MUCH!! you are amazing
Haha you're welcome :)
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