explain how to graph this linear equation. 4x+2y=4 @gypsy1274 2x-3y=10
First solve each equation for y.
i'll try my best 4x+2y=4 subtract (4x from both sides) 2y=4-4x (divide by 2) y=2-2x
Yes. I would keep it in \(y=mx+b\) form to make graphing easier. \(y=-2x+2\) Start with the y-intercept. b=y-intecept
please wait i was almost done and then messed up
No problem. Take your time.
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That looks right. The other equation is a little more difficult because you are dealing with fractions. I would still start by solving for y to determine the slope.
the fractions are mostly what i need your help with.
2x-3y=10 Solve for y:: What is your first step?
2x-3y=10(subtract 2x from both sides -3y=10-2x y=10/ -3 -2x/-3
Great. Can you determine the slope from that equation?
slope =-3 and 1/3?
\(2x-3y=10\) \(-3y=-2x+10\) \(y=\frac{2}{3}x+-\frac{10}{3}\) In \(y=mx+b\) form, it is easy to see what the slope should be. m = slope = \(\frac{2}{3}\)
Does that make sense? Do you understand the \(y=mx+b\) form?
y=2/3x+-10/3 so when you divide by negatives it has the same effect as multiplying?
Yes. And even number of negatives makes a positive and an odd number of negatives makes a negative.
For additional instruction on fractions, I would like to refer you to Purple Math http://www.purplemath.com/modules/fraction3.htm and Khan Academy www.khanacademy.org Both are free resources. And of course feel free to ask me questions at any time.
im sorry can we continue using open study yahoo is too difficult for me to use
OK, what ever works for you.
ok im going to start a graph
y = 2/3x - 10/3 slope here is 2/3 y intercept is -10/3 or - 3 1/10 x intercept can be found by subbing in 0 for y y = 2/3x - 10/3 0 = 2/3x - 10/3 -2/3x = -10/3 x = (-10/3) / (-2/3) x = -10/3 * 3/2 x = -30/6 = -5 ---- x intercept is (-5,0) now plot your points...(-5,0) and (0,-10/3)...if it makes it easier to graph, the y intercept can be plotted as (0,-3 1/10)
oops...y intercept is -10/3 or -3 1/3 not -3 1/10..sorry bout that
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