Question

Help one last question need it fast so just the answer would be fine

Answer 1

do you have any ideas on how your gunna solve or you need help solving

Answer 2

need help solving

Answer 3

AdeyNyx, Forgive me, but I'd prefer to focus on the 'how-to' than on the answers.
This figure is made up of two adjacent SPECIAL triangles, one a 45-45-90 triangle, the other a 30-60-90 triangle. It's well worth learning why these two special triangles are important, as well as how to apply that knowledge.
First: the 45-45-90 triangle: Since two of the 3 angles are equal, the legs of this triangle are also equal. We don't know the leg length, but do know the hypotenuse length. Let our friend Pythagoras help you solve for the leg length.

Can you do this on your own?

Once you have that leg length for the 45-45-90 triangle, you'll be able to solve the 30-60-90 triangle, using proportions. Does that ring a bell?

Answer 4

\[\frac{ h }{8 }=\sin 45=\frac{ 1 }{\sqrt{2} }=\frac{ \sqrt{2} }{2 },h=4\sqrt{2}\]
\[\frac{ h }{x }=\sin 30=\frac{ 1 }{ 2 },x=2h=2*4\sqrt{2}=8\sqrt{2}\]
\[\frac{ y }{x }=\cos 30=\frac{ \sqrt{3} }{2 },y=\frac{ \sqrt{3} }{2 }*8\sqrt{2}=4\sqrt{6}\]

Answer 5

thats right :)