Does anyone know how to do this? (I am either doing it wrong or doing my math incorrectly)
i know how to do this
ok so, numbers are 4,13,5,6,9 If the mean of these data is approximately 7, what is the population standard deviation for these data? (Round the answer to the nearest tenth.)
The population standard deviation is defined as: $$s = \sqrt{\frac 1 {N-1} \sum_{i=1}^N (x_i - \bar x)^2}$$
Ah, no, nevermind. 'Tis N, not N-1.
oh uh, sorry, but do you know what we plug into that equation?
N is the number of data values. Okay, so the simplified thing is: #1.) Take the mean. We have that; it's 7. We have that N = 5. #2.) Now we subtract the mean from each datum and square the result. Let's see: 4 - 7 = -3, 3^2 = 9 13 - 7 = 6, 6^2 = 36 5 - 7 = -2, 2^2 = 4 6 - 7 = -1, 1^1 = 1 9 - 7 = 2, 2^2 = 4 #3.) Now we take the mean of those values. 54/5, or 11.02. #4.) Finally, we take the square root of the final product. sqrt(11.02) = ?
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhh
fail, that's what I forgot to do, take the square root, wow
thank-you so much
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