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Prove sin(x+y)=sin(x)cos(y) + cos(x)sin(y), use the left side to start and use the trig identities as in the proof. How do I do this?
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From the identity sin (A+b) = sinAcosB + cosAsinB We can prove that: sin(x+y) = sin(x)cos(y)+cos(x)sin(y) Hence sin(x)cos(y)+cos(x)sin(y) = sin(x)cos(y)+cos(x)sin(y) That's it. :)
if you're looking for derivation of sin(x+y) :- https://www.khanacademy.org/math/trigonometry/less-basic-trigonometry/trig_iden_tutorial/v/proof--sin-a-b------cos-a--sin-b-----sin-a--cos-b
wow now that i look at it it seems so obvious haha thank you!
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