Let f(x) = 4 - 12/x^2. Calculate the lower and upper sum estimates of the area under the curve over the interval [2,5] using subintervals of width ½.
i got a hint from my teacher: Technology hints: A graph can be helpful in checking to see if your answers are reasonable. Since we are getting estimates, it would be appropriate to use a calculator or spreadsheet to do the calculations accurate to four decimal places, then round your final upper and lower sum to three.
Zubhanwc3 is correct. We actually just did finding the area under a curve in my Calculus class. I'm going to graph it in my graphing calculator and see the graph that we are dealing with.
can i get help for my question then ^^?
Oh lol you replied to your own message. Okay :)
Is that 4 - (12/x^2) ? ? ?
yes
You're using Riemann sum right? The old fashion way of computing an integral?
i think so
Ooh you get an interesting graph from that. Luckily between 2 and 5 it is all positive so there will be no negative area. Yes Luigi this is Riemann sums.
I'm going to set my table for 1/2 width, and then check the points. Should I check from the left, middle, or right?
@zubhanwc3 The default is middle but I just want to make sure. I learned left first and middle last
i have no idea T_T im not supposed to do riemann sum, but apparently i am T_T
the lesson after this one is about riemann sums.
Do you happen to be using a Calculus textbook with a weird looking circle type thing on the cover?
yes. Calculus graphical, numerical and algebraic. fourth edition
I have 9th edition and it's just AP Edition. I'm sorry I just don't understand what your teacher or textbook is asking from you.
mine also says ap edition. if you google my book, you can see the cover.
alrite then, wats the riemann sum method? i might as well get the problem done with T_T.
I could help, but I have to go :(
Okay yeah it is different, but the section for me before Rieman sums is just titled "Area." It uses changeofx = b-a/n Does that look familier?
o we got same thing:P im on the section titled area.
and no, that doesn't look familiar.
are you in ap calc ab?
Yeah
connections acad?
wait, different book, so i guess not:P
how do i figure out the number of rectangles?
You find the number of triangles from the numbers. You are looking between the x points of 2 and 5 5-2 = 3 Now you have to do 3/1/2 That gives you 6 different rectangles.
by plugging it in, my estimated area should be 8.4286, right? so would that be the answer?
im really confused about the upper and lower sum estimates part of it >.<
Lower sums is measuring it from the left. Upper sums is from the right That's what I was trying to ask you XD
yay, so i gotta get 2 estimates from both, well not a problem T_T
I gotta go but good luck. I hope that helped.
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