What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

243
729
2,187

Question

What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?


243
729
2,187

anonymous · Answer

fan and medal to first correct awnser

raden · Answer

use this formula :
Tn = a1 * r^(n-1)

known a1 = , r = 3 and n = 6

raden · Answer

oppsss. n = 7

anonymous · Answer

this is first year algebra i dont know how to do that

anonymous · Answer

thanks for the explain

raden · Answer

Tn = a1 * r^(n-1)
T7 = 1 * 3^(7-1)
T7 = 3^6 = 729

anonymous · Answer

were u given an equation to work with dan??

owlcoffee · Answer

but, Rad, is this a Geometric sucession?

anonymous · Answer

yes i got it now @JaziBoo

anonymous · Answer

Kk, and if u need anything juz let me know ;D

raden · Answer

yeah, it is a Geometric sucession. 
you just have 8 terms, @Owlcoffee . the question is asking us the 7th term

raden · Answer

by manual, this sequence is 
1,  3,  9,  27,  81,  243,  729

if you multiply by 3 for next term, it would be 8th term. @Owlcoffee

owlcoffee · Answer

yeah, I miscalculated, whenever you do it manually and given the first term, you always go on 1 less to the exponent (proof of the formula) Wich is easy to prove, but I'm soooo lazy...