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Mathematics 17 Online
OpenStudy (anonymous):

help please!

OpenStudy (anonymous):

\[\frac{ 7ab ^{-2} }{ 3w }\]

OpenStudy (mathmale):

First, Nina, what's your goal in solving this problem?

OpenStudy (anonymous):

simplify

OpenStudy (mathmale):

In this type of problem, what would "simplify" mean?

OpenStudy (mathmale):

I need and want to know how YOU see this.

OpenStudy (anonymous):

simplify expression

OpenStudy (anonymous):

see what?

OpenStudy (mathmale):

What it means to "simplify" an expression such as the one you've presented here.

OpenStudy (anonymous):

to reduce an equation to a simpler form

OpenStudy (mathmale):

In other words, Nina, what will the correct result look like, in comparison to the expression you're starting with?

OpenStudy (mathmale):

OK, let's start with what you've just said. What part of the expression (7ab^(-2))/(3W) needs simplifying, and why?

OpenStudy (mathmale):

that is, which part of the following expression needs simplification, and why? \[\frac{ 7ab ^{-2} }{ 3w }\]

OpenStudy (mathmale):

Hint: don't worry about the 7, the a, the 3 or the w. They're fine as is. What's "wrong" with the remainder of this expression?

OpenStudy (anonymous):

the top part 7ab^-2

OpenStudy (anonymous):

^-2 exponent turns to a positive so b^2

OpenStudy (mathmale):

Just the b^(-2) part. Sorry to have been so roundabout. My point is that we need to understand what actions to take to simplify an expression that contains a negative exponent. Perhaps you know already how to re-write the following WITHOUT a negative exponent: \[b ^{-2}=?\]

OpenStudy (anonymous):

yes

OpenStudy (mathmale):

Building on what you have already said, where are y ou going to write that \[b ^{2} \] which you got a moment ago?

OpenStudy (mathmale):

Hint: rewrite \[b ^{-2}\] as a fraction.

OpenStudy (anonymous):

next to the 7a?

OpenStudy (mathmale):

Yes, but for now please just focus on re-writing that \[b ^{-2}.\]

OpenStudy (mathmale):

Let me drop another hint: In this problem we need to simplify the given expression by getting rid of negative exponents. That's why I keep asking you how you'd do this re-writing.

OpenStudy (anonymous):

i think i got it

OpenStudy (anonymous):

the 7a is left at the top write so

OpenStudy (mathmale):

Yes, the 7a stays in the numerator. And the 3w stays in the denominator. All you have to do is to rewrite that \[b ^{-2}.\]

OpenStudy (anonymous):

\[\frac{ 7a }{ 3b ^{2}w }\]

OpenStudy (anonymous):

ok is this right

OpenStudy (mathmale):

Yes, that's absolutely perfect. Congrats. You're really showing your stuff now. What I'd encourage you to do

OpenStudy (anonymous):

Thanks ^^

OpenStudy (mathmale):

is to go back and re-write the original problem statement to read, "simplify the following expression by eliminating the negative exponent."

OpenStudy (jdoe0001):

\(\bf \cfrac{7ab^{-2}}{3w}\qquad \textit{recall}\quad a^{-n} = \cfrac{1}{a^n}\qquad thus\\ \quad \\ \cfrac{7ab^{-2}}{3w}\implies \cfrac{7a}{3w}\cdot b^{-2}\implies \cfrac{7a}{3w}\cdot \cfrac{1}{b^{2}}\)

OpenStudy (anonymous):

I will practice more

OpenStudy (anonymous):

but i get it now and it's easy

OpenStudy (mathmale):

I'm so glad you see it that way! Good going, Nina. Take care. H. N. Y.

OpenStudy (anonymous):

@mathmale can you help me with another problem?

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