Prove that opposite sides of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures
@caraonline
You need to split your parallelogram into two triangles: |dw:1388872939629:dw|
We can show that opposite sides are congruent by showing that ADB and BDC are congruent
Its because alternate interior angles right?
The line BD is shared. Angle DAB = angle BCD because opposite angles in a parallelogram are equal.
We can also take the alternate angles rule (Z angles) to show that angle ABD = angle BDC
So we have ASA, which shows that the two triangles are congruent. Because ABD = BDC and not ADB, triangle ABD is a reflection of triangle BCD, so opposite sides are equal.
http://library.thinkquest.org/20991/media/geo_pex1.gif so in this 2=4 right? is there a postulate or theorem that proves this?
Exactly, aye. You can just just the alternate angles theorem, I imagine :)
Okay thanks sooo muchhhh!
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