Question

I need helpp Medal will be given!

Answer 1

yes.

Answer 2

Shin-chan! But seriously, the question is needed.

Answer 3

sure thing

Answer 4

\[\sum_{n-1}^{14} 3n+2\]

Answer 5

It is an arithmetic sequence with first number 5, last number 44 and number of terms 14. What is the sum?

Answer 6

How do I do that

Answer 7

hOw do you know the first number is 5

Answer 8

Sum of an arithmetic series = n * { first term + last term } / 2

Answer 9

Oh, in the sigma the "n" runs from 1 to 14.
You put n = 1 you get the first term. n = 2 you get the second term. n = 14 you get the last term.

Answer 10

3(1)+2+3(2)+2..........3(14)+2=3(1+2+....14)+2x14=3(14(14+1)/2)+28=343

Answer 11

24.5 @ranga ?

Answer 12

@Rohitkhanna idk what exactlyy you did can you explain?

Answer 13

if we expand the expression then we can have 3 in common from the first part as it is being repatedly multiplied to different no. from 1 to 14.then for finding the sum 1+2+3....+14,i used the formula to find sum of first n natural no. which is n(n+1)/2,where n is the no. of turns.and then simply add 2 to it.the above solution i gave is half wrong as i also repeated 2 14 times which is not so as the sign of sigma is only with the first part of the expression