how can I solve this by d2y/dx2 by implicit differentiations: x^3+y^3=1
Well the first dy/dx is the deravite with respect to y, so 3x^2+3y^2dy/dx=0
is that good enough? and i want a medal for it.
dy/dx(3y^2)=-3x^2... dy/dx= -x^2/y^2
And zub your wrong all you did was search it up without reading, she asked for the second der not the first.
By the way - to do these kindsn of problems recursively use dy/dx you find
Quotient rule next, (y^2)(-2x)-(-x^2)(2y dy)/ -(y^2)^2
fine here is the second deriv part of it.
@zubhanwc3 , stop answer sniping, or I will report you.
answer sniping? all im doing is answering othe peoples question.
wats wrong with helping others, they get help, and i get possible medals, its to equal out my asking questions ^^
@zubhanwc3 , answer sniping is when someone is actively helping another out and you blurt out an answer. It's distracting to the asker, and downright disrespectful to the answerer. I will not, to the best of my abilities, allow you to do so on this website.
i answered before he did
i had the first post, and i got a reply to it, so i continued my answer
No a crude version of wolfram alpha answered, and you obviously showed you lack of knowledge of calculus. In any case, I am no longer going to derail this thread. @RobertSn , my apologies.
Noura: Follow the proper steps that RobertSn has shown you.
@inkyvoyd i just used the easy way out, i had a method, so instead of making it hard to read, i used a clean readable method, i dont see where this has to do with my knowledge, i knew how to do it, but its annoying to type away.
I believe the second der posted by zubh is actually incorrect also
@RobertSn , I don't believe the answer is correct either. I saw no recursive implicit differentiation and I don't know of another way to do the problem.
I can't get it with second derivative, HELP ME my exam after a few hours !!!
the second one is a continuation of the first one >.>
Okay noura im gonna work on it so il post soon
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