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Calculus1 12 Online
OpenStudy (anonymous):

Help? I'm suppose to find the slope of the curve of a point of an inverse.

OpenStudy (abb0t):

Ok. Go on...

OpenStudy (anonymous):

If f(x) = 2x^2 + 3x + 1, let g(x) = f^-1 (x). Find the slope of the curve g(x) = f^ –1(x) at the point (6, 1).

OpenStudy (abb0t):

First, take the derivative.

OpenStudy (anonymous):

4x + 3

OpenStudy (agent0smith):

Now find the slope at the point (6, 1)

OpenStudy (anonymous):

wouldn't I substitute 6 in for x?

OpenStudy (agent0smith):

Yes

OpenStudy (anonymous):

so it would be 27?

OpenStudy (agent0smith):

Yes

OpenStudy (anonymous):

okay now what?

OpenStudy (agent0smith):

Now the slope of the inverse function will be the reciprocal of the slope of the original function (since to get the inverse, you reflect the function over the line y=x)

OpenStudy (anonymous):

1/27?

OpenStudy (agent0smith):

Yes. You can see here for a quick explanation why they're reciprocals http://answers.yahoo.com/question/index?qid=20120306133453AAYxtNI

OpenStudy (agent0smith):

http://webspace.ship.edu/msrenault/GeoGebraCalculus/derivative_inverse_functions.html I like the proof at the bottom of that page

OpenStudy (anonymous):

okay so the answer would be 1/27?

OpenStudy (anonymous):

HI :DD

OpenStudy (agent0smith):

lol read more carefully kayla ;)

OpenStudy (abb0t):

https://www.hookedonphonics.com/

OpenStudy (anonymous):

g'x is actually 1/f'(f(x))..so answer would be 1/(4.1+3)=1/7

OpenStudy (agent0smith):

@srijit see the bottom of the link below. http://webspace.ship.edu/msrenault/GeoGebraCalculus/derivative_inverse_functions.html

OpenStudy (agent0smith):

http://www.ccsdk12.org/mclemens/courses/APcalcAssign/MD-6A.pdf Actually I might've worked this out wrongly. The slope is reciprocal at reflected points, but we used the original point (6,1), not the reflected point.

OpenStudy (agent0smith):

^use the very last page of http://www.ccsdk12.org/mclemens/courses/APcalcAssign/MD-6A.pdf To find g'(6): Find x for y=6, using f(x)= 2x^2 + 3x + 1 so x=1 and x=-5/2, but visually looking at a graph of f(x), the point for the inverse will be x=1 (tough to explain this part w/o showing using the inverse) find the slope of f'(1) = 4(1) + 3 = 7 Then the reciprocal is 1/7.

OpenStudy (anonymous):

sorry my typo mistake .g'x=1/f'(g(x)).g(6)=1

OpenStudy (agent0smith):

Yeah, that's probably faster, but in this case it's not quite as simple as you make it seem, since it's a quadratic function.

OpenStudy (agent0smith):

Since g(6) = 1 and g(6) = -5/2

OpenStudy (anonymous):

its mentioned in the question only to find the slope @ (6,1) :D

OpenStudy (agent0smith):

I know. That's not the point I was making.

OpenStudy (anonymous):

and yeah truly g(x) does not exist as f(x) is non-invertible

OpenStudy (agent0smith):

Yeah, it's an awkward question given that. I mean yeah they tell you the point (6, 1), but still.

OpenStudy (anonymous):

i got your point :)

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