check for extraneous solutions.
sqrt x+7-x=1
Please show step by step on how to do this. Thankyou.

Question

check for extraneous solutions.
sqrt x+7-x=1
Please show step by step on how to do this. Thankyou.

anonymous · Answer

Let $u=\sqrt{x}$, then x = $u^2$
Now, the equation becomes
$$u+7-u^2=1$$
Can you do it?

anonymous · Answer

Wat?

anonymous · Answer

@Krazete

anonymous · Answer

I don't get the way you're explaining it to me @RolyPoly

anonymous · Answer

Please make use of parentheses. The way you write problems is sorta confusing.
Is it √(x+7)-x=1 or ...?

anonymous · Answer

I guess. Sorry, it doesn't show parentheses on my math problem.

anonymous · Answer

Is the equation (1)$\sqrt{ x+7-x} =1$  or (2) $\sqrt{x}+7-x=1$?

anonymous · Answer

nvm, i got the answer. Thx

anonymous · Answer

nvm.. I tried wolframalpha. But only get two step by steps each day:(

anonymous · Answer

I'll have to get the answer tomorrow.

anonymous · Answer

It would be better if you know how to solve it, instead of just relying on WolframAlpha.

anonymous · Answer

eh, true. But lets be honest with ourselves, I'm never going to use this advanced of math in the future.

anonymous · Answer

Honestly, I just need credits/passed classes

anonymous · Answer

you can argue all you want, but it's true.

anonymous · Answer

Don't want to argue, just want to help you pass the course and you can learn how to solve it at the same time :)

anonymous · Answer

can you just show me please? I'm 18 lessons behind:(

nikato · Answer

$$\sqrt{x+7}-x=1$$

nikato · Answer

add x to both sides

anonymous · Answer

It would be a different story if I wasn't that behind

anonymous · Answer

$$\sqrt{x-7-x}=1$$$$\sqrt{x-7}-x=1$$$$\sqrt{x}-7-x=1$$
Which one is your question?

anonymous · Answer

like this @nikato |dw:1388896983931:dw|