Question

Identify whether the series is a convergent or divergent geometric series and find the sum, if possible.
@perl @inkyvoyd

Answer 1

if the absolute value of hte common ratio r (the number under the xponent) is greater than or equal to 1, then the geometric series diverges.

Answer 2

\[\sum_{i=1}^{\infty}12(3/5)^{i-1}\]

Answer 3

the formula for infinite geometric series is
\(\Huge \sum_{i=1}^{\infty}a(r)^{i-1}=\frac{a}{1-r}\)

Answer 4

this ONLY applies if the absolute value of r is less than or equal to 1.

Answer 5

so its divergent

Answer 6

@inkyvoyd

Answer 7

no @woohoo r=3/5. 3/5=0.6, and .6 is less than 1

Answer 8

congernt

Answer 9

convergent @inkyvoyd

Answer 10

yes. so then, use the provided formula.

Answer 11

is it 30 @inkyvoyd

Answer 12

Yes, I think so.

Answer 13

You think so, im feeling kinda skeptical

Answer 14

?

Answer 15

If I were you, I'd put down that answer.

PS: you might want to check the other question. I think we should've used n=5 and not n=6

Answer 16

We did one like this earlier... did you already forget it? :P

Answer 17

this onw is diffrent @agent0smith

Answer 18

one

Answer 19

No, it's the same, at least deciding whether the series is convergent or not. It the same as the one where you had 15(4)^(i-1).

Answer 20

its same in where its asking convergent or not but the problem in of itself is different. :)

Answer 21

Yes, but i mean you did not correctly identify whether it's convergent or not. Had you looked at the past question, you would have been able to.

Answer 22

ohh now I understand you, I'm kinda slow whe it comes to Math

Answer 23

If you write notes, or at least look back over your past questions when you find a similar one, that'll help the information sink in.

Answer 24

Thannks anyway for all your help! I really appreciate it! @agent0smith