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OpenStudy (anonymous):
OpenStudy (anonymous):
hellp mee
OpenStudy (anonymous):
two similar triangles have their sides in a fixed ratio. are you familiar with this property?
OpenStudy (anonymous):
which one i s tht
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
Q16
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
let triangle PQR be similar to triangle ABC. then PQ/AB=QR/BC=PR/AC
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
this tells us that, AB/AC= PQ/PR. the ratio AB/AC= 5/4 from the given figure. thus the correct option will have the same ratio of height/ base.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
the same logic would apply to Q17. to keep both the photos similar,
height/length = height'/ length'
OpenStudy (anonymous):
so the answer for 16 is
OpenStudy (anonymous):
height = 3 inches, length = 5 inches, length' = 7.5 inches. Plug into the equation above and solve for height'
OpenStudy (anonymous):
ok it 4.5 inches
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OpenStudy (anonymous):
for number 17
OpenStudy (anonymous):
and wat is the answer for 16
OpenStudy (anonymous):
none of the options seem to match for Q16, what are the chances of it having an error?
OpenStudy (anonymous):
it b
OpenStudy (anonymous):
for Q16, option has the ratio as 5/6, for option b it is 15/4, for option c it is 4/3. while according to the given figure it should be 5/4. so none of the options have correct ratio here.
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OpenStudy (anonymous):
idk no then
OpenStudy (anonymous):
should we move onto Q18?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
so one else need help 16 and 17
OpenStudy (anonymous):
in the cereal box, you'd have 3 rectangles one from the top, one from the side and one from the front.|dw:1388898750959:dw|