Two cars A and B have a velocity of 60 mph in the same direction. A is 250 ft. behind B when the brakes are applied to car B, causing it to decelerate at the constant rate of 10〖fps〗^2. In what time will A overtake B and how far will each car have travelled.

Question

anonymous · Answer

plz help

agent0smith · Answer

You can use physics equations of motion.

anonymous · Answer

can someone help me with this question??? really need your help ..... :-(

agent0smith · Answer

Car A's position is given by 60t (just velocity*time)

Car B's position is 60t - 0.5at^2 + 250, where a is 10 fps^2 but converted into miles per hour^2, the 250 is because it starts 250ft ahead

When A passes B, their positions are equal

60t = 60t - 0.5at^2 + 250

Find t.

agent0smith · Answer

Actually no just use a as 10 since that'll work.

0 = - 0.5*10t^2 + 250

anonymous · Answer

tnx men