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OpenStudy (musicfreak):
What is the oxidation state of nitrogen in NaNO2? 1) +1 2) +2 3) +3 4) +4
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OpenStudy (anonymous):
Na-->+1 O2-->2x(-2)=-4 let the oxidation no. of N be s. this compound is neutral overall,therefore 1+(-4)+s=0 ----> s=+3 +3 is the correct answer
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