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Mathematics 20 Online
OpenStudy (anonymous):

Solve (x-2)(x+3)<0 show all working

OpenStudy (solomonzelman):

\[ (x-2)(x+3)<0 \]this means that\[ (x-2)<0 ~~~~~and~~~~~(x+3)<0\]Solve each one,\[ x-2<0 ~~~~~and~~~~~x+3<0\]

OpenStudy (anonymous):

here's another method :) let (x-2)(x+3) be f(x) let's check when is f(x)<0 by using a table and checking their intervals intervals \((-x, -3)\) \((-3,2)\) \((2, +x)\) test values -4 0 3 (x-2) - - + (x+3) - + + f(x) + - + substitute the test values into (x-2) and (x+3) to determine if it is positive or negative in the given intervals if it is positive it means that f(x)>0, and if the function is negative it means that the f(x)<0 another method is done by SolomonZelman

OpenStudy (anonymous):

OpenStudy (mathmale):

Craig: I'm curious: What are YOU thinking at this point? What's clear for you now, and what is not?

OpenStudy (anonymous):

I've still got another 67 questions and don't know how to do most of them

OpenStudy (mathmale):

Oh, shoot. I'd prefer to see you build up momentum by identifying and completing the problems that are easiest for you and then to return to the harder ones. What do YOU want to do next? Choose a few problems that seem easy to you?

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