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Mathematics 8 Online
OpenStudy (anonymous):

I need help with practice test

OpenStudy (mathmale):

N-1 Whiz, Please don't be detracted. Let's get started. Choose a problem from that practicve test and do what you can towards solving it, then share it with me.

OpenStudy (mathmale):

Come on, N-1 Whiz: Post something from your practice test for us to focus on. Ignore detractions as much as you can.

OpenStudy (mathmale):

You'll need to learn the vocabulary. Degree here refers to the highest power of x, which is 12. It's not appropriate to multiply here.

OpenStudy (mathmale):

Yes. There's no short cut here: You need to know precisely what "degree" refers to. I'd suggest you write this down and review it regularly: "The degree of a polynomial is the same as the highest power of x."

OpenStudy (mathmale):

In this case, that highest power is 12. Sure, go ahead. But I'd like for you to show me what you have already done before I jump in.

OpenStudy (anonymous):

Find the GCF of the terms of the monomial 52x^8 +12x^3 can you define for me?

OpenStudy (mathmale):

GCF means "greatest common factor." (Seriously, please write that down for later reference.)

OpenStudy (mathmale):

Look at the two terms in your expression. Both contain powers of x, right? What is the largest power of x that you can factor out of BOTH terms?

OpenStudy (anonymous):

I knew what GCF was lol I meant the terms

OpenStudy (anonymous):

largest power should be 3 because it goes into each number

OpenStudy (mathmale):

Your expression, 52x^8 +12x^3, has two terms. One is 52x^8; the other is 12x^3. In your expression, the two terms are added together. Now, in response to your statement: The largest power , the of x common to both terms is x^3, the third power of x. Try factoring that out of your expression.

OpenStudy (mathmale):

Sorryfor the poor phrasing. "The largest power of x common to both terms is x^3." Factor that out of both terms.

OpenStudy (anonymous):

oh I understand now.

OpenStudy (mathmale):

52x^8 +12x^3= what, after factoring x^3 out?

OpenStudy (anonymous):

x^8?

OpenStudy (mathmale):

I'll try to illustrate this more clearlly. Please wait.

OpenStudy (anonymous):

ok

OpenStudy (mathmale):

\[52x^8 +12x^3=(x ^{3})(what?)\] I'm asking y ou to factor that x^3 out of your expression. What's left after factoring?

OpenStudy (jagatuba):

I'm honestly not trying to confuse things here @mathmale, but shouldn't it be:\[52x ^{8}+12x^3=(4x^3)(what?)\]

OpenStudy (mathmale):

You are absolutely right, but I had a reason for wanting to factor out only x^2. Thanks for your input.

OpenStudy (jagatuba):

K sorry to interrupt.

OpenStudy (anonymous):

Idk either of them, or the "what"

OpenStudy (mathmale):

For practice: Please factor: 12x-2.

OpenStudy (anonymous):

show me

OpenStudy (mathmale):

Let's see what jagatuba has to say.

OpenStudy (anonymous):

ok

OpenStudy (mathmale):

In the meantime, N-1 Whiz, do you have a textbook for this course? If so, do you have the book with you?

OpenStudy (jagatuba):

Whenever you have a problem like this you have to think what can I take out. 12x-2 Since we have a - (in this case, but could have a +) we have to keep the terms separate. In the first term we have 12x and in the second we only have 2, therefore we know that we can only take out a whole number. That number being 2. So we have: 2(6x-1) Does that make sense?

OpenStudy (mathmale):

Yes. Hope it does for N-1 Whiz also. Note, N-1 Whiz, that 2 is the "greatest common factor," or GCF: it's the largest factor common to both terms of 12x-2 that can be factored out. What do you think, N-1 Whiz? Thank you, jagatuba.

OpenStudy (jagatuba):

She may have given up. She is no longer in the thread.

OpenStudy (jagatuba):

Nor even online.

OpenStudy (anonymous):

yes i just gave up, im sorry @jagatuba @mathmale

OpenStudy (mathmale):

It's your decision. But I'd love to continue working with you and hope you'll reconsider.

OpenStudy (anonymous):

we can continue with a different one @mathmale

OpenStudy (mathmale):

I'll try my best to help, but right now I have a backlog of questions from others. Why not just post your new question? i'd try to get to it.

OpenStudy (anonymous):

ok :) thank you

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