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Find the derivative of h(x)=tan^3x
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use the chain rule
\[\frac{d}{dx} (\tan(x))^3\] You have a case where: \[\frac{d}{dx}(f(g(x)) = f'(g(x))g'(x)\] , the chain rule, applies. Using f(x) = x^3 and g(x) = tan(x) see if you can figure it out.
3tan^2x sec^2x
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