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Mathematics 8 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

\[3\sqrt[5]{(x+2})^{3}+3=27\]

OpenStudy (amoodarya):

put 3 to rs radical =27-3 to the power of 5 then simplify

OpenStudy (anonymous):

can you explain a lil more? sorry, I just have a hard time with questions like this

OpenStudy (jdoe0001):

\(\large {3\sqrt[5]{(x+2})^3+3=27\quad \textit{subtract 3 from both sides}\\ \quad \\ 3\sqrt[5]{(x+2})^3=24\quad \textit{divide by 3 both}\\ \quad \\ \sqrt[5]{(x+2})^3=\cfrac{24}{3}\implies \sqrt[5]{(x+2})^3=8\quad \textit{raise to power 5 both}\\ \quad \\ \left[\sqrt[5]{(x+2})^3\right]^5=8^5\implies (x+2)^3=8^5\quad \textit{get root 3 on both}\\ \quad \\ \sqrt[3]{(x+2)^3}=\sqrt[3]{8^5}\implies x+2=\sqrt[3]{8^5} }\)

OpenStudy (anonymous):

So, the answer is x+2=\[\sqrt[3]{8^5}\]

OpenStudy (jdoe0001):

well.. no... solve for "x", there's an assumption you can simplify linear equations... so just simplify it by isolating "x" on the left-hand side

OpenStudy (anonymous):

alright, hold on

OpenStudy (anonymous):

how would I simplify \[3\sqrt{8^5}\]

OpenStudy (jdoe0001):

well, you can ... but you'd want to firstly isolate "x" :)

OpenStudy (amoodarya):

you should not simplify that radical answer is just x=-2+(8^5)^1/3

OpenStudy (anonymous):

\[x=-2+3\sqrt{8^5}\]

OpenStudy (anonymous):

how did you get x=-2+(8^5)^1/3?

OpenStudy (anonymous):

@jdoe0001 I am confused

OpenStudy (jdoe0001):

hmmm well... do you know how to simplify linear equations?

OpenStudy (anonymous):

kinda, I typed what I thought was the answer with x on the left side. a couple comments above. did I do it wrong?

OpenStudy (jdoe0001):

well... \(\large x+2=\sqrt[3]{8^5} \implies \color{red}{x=3\sqrt[]{8^5}}\quad ?\)

OpenStudy (anonymous):

So, I did do it wrong? and the guy above said to not simplify the radical

OpenStudy (jdoe0001):

well.... you may want to refresh your linear equation simplification http://www.youtube.com/watch?v=zNtqneXTSWM

OpenStudy (anonymous):

I got \[x=1\sqrt{8^5}\]

OpenStudy (nikato):

I got x=30

OpenStudy (anonymous):

how did you get that?

OpenStudy (nikato):

here. i'll just show u the steps. and just tell me if u have any questions

OpenStudy (nikato):

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