help please
\[3\sqrt[5]{(x+2})^{3}+3=27\]
put 3 to rs radical =27-3 to the power of 5 then simplify
can you explain a lil more? sorry, I just have a hard time with questions like this
\(\large {3\sqrt[5]{(x+2})^3+3=27\quad \textit{subtract 3 from both sides}\\ \quad \\ 3\sqrt[5]{(x+2})^3=24\quad \textit{divide by 3 both}\\ \quad \\ \sqrt[5]{(x+2})^3=\cfrac{24}{3}\implies \sqrt[5]{(x+2})^3=8\quad \textit{raise to power 5 both}\\ \quad \\ \left[\sqrt[5]{(x+2})^3\right]^5=8^5\implies (x+2)^3=8^5\quad \textit{get root 3 on both}\\ \quad \\ \sqrt[3]{(x+2)^3}=\sqrt[3]{8^5}\implies x+2=\sqrt[3]{8^5} }\)
So, the answer is x+2=\[\sqrt[3]{8^5}\]
well.. no... solve for "x", there's an assumption you can simplify linear equations... so just simplify it by isolating "x" on the left-hand side
alright, hold on
how would I simplify \[3\sqrt{8^5}\]
well, you can ... but you'd want to firstly isolate "x" :)
you should not simplify that radical answer is just x=-2+(8^5)^1/3
\[x=-2+3\sqrt{8^5}\]
how did you get x=-2+(8^5)^1/3?
@jdoe0001 I am confused
hmmm well... do you know how to simplify linear equations?
kinda, I typed what I thought was the answer with x on the left side. a couple comments above. did I do it wrong?
well... \(\large x+2=\sqrt[3]{8^5} \implies \color{red}{x=3\sqrt[]{8^5}}\quad ?\)
So, I did do it wrong? and the guy above said to not simplify the radical
well.... you may want to refresh your linear equation simplification http://www.youtube.com/watch?v=zNtqneXTSWM
I got \[x=1\sqrt{8^5}\]
I got x=30
how did you get that?
here. i'll just show u the steps. and just tell me if u have any questions
|dw:1388962879078:dw|
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