Question

The first order derivative of a function y (x ) is given as y'(x)=3x^4-5x^2

If the function y(x) passes through the origin i.e. (0,0), determine y(x) by finding
the anti-derivative of y'(x) .
Help please?

Answer 1

Ok, so this is some pretty simple integration. Do you know how to do integration by parts?

Answer 2

no because this new chapter...so I ned help to solve it

Answer 3

Alright, no problem. you use the basic formula for integration which is \[\frac{ x^{n-1} }{ n-1 }\]

Answer 4

integrating y' gives


3 x5/5 - 5 x^3/3 + C where C is is some constant

y = 3 x5/5 - 5 x^3/3 + C

plug in y = 0 and x = 0 to find the value of C

Answer 5

So for that first part of the problem 3x^4 you would subtract 1 from the exponent (the 4) and then divide by that.

Answer 6

@stardogchampion - thats differentiation

Answer 7

Oh my I'm an idiot.

Answer 8

Integration is
x^(n+1)
-------
n + 1

Answer 9

Haha, sorry.

Answer 10

lol - we all are on times....

Answer 11

if we solve 3 (0)^5 / 5 - 5 (0)^3 / 3 + C = 0
for C what do we get/

Answer 12

C = 0 right?

Answer 13

yup

Answer 14

finally we can write y(x) which is