Question

Solve: 7x/x-1 - 3/x

Answer 1

\[\frac{ 7x }{ x-1 } - \frac{ 3 }{ x }\]

Answer 2

HI, wolfram alpha it :DDDD

Answer 3

how do u solve it? it doesnt equal anything

Answer 4

Oh I totally forgot its equal to 7

Answer 5

\[\frac{ 7x }{ x-1 }-\frac{ 3 }{ x }=7\]

Answer 6

Yup

Answer 7

u need common denominator, so multiply first fraction by x/x

Answer 8

the second by x-1/x-1

Answer 9

and the 7 by x(x-1)/ x(x-1)

Answer 10

So you would get:\[\frac{ 7x^{2} }{ x ^{2} - x } - \frac{ 3x - 3 }{ x ^{2} -x } = \frac{ 7x ^{2} - 7x }{ x ^{2} - x}\]

Answer 11

@nikato

Answer 12

yup. and if u didnt factor the denominator, so it'll still by x(x-1) what cant x be

Answer 13

it can't be 0

Answer 14

and ?

Answer 15

and 1

Answer 16

ok, so x can = 0 or 1

now multiply bth sides of the eqaution by x(x-1)

Answer 17

it cancels on the right but what does it do on the left?

Answer 18

you'll get
\[7x ^{2}-(3x-3)=7x ^{2}-7x\]

Answer 19

it helps cancel all the denominator