Question

A player kicks a football for the opening kickoff. He gives the ball an initial velocity of 29m/a at an angle of 69 degrees above horizontal. Determine the balls maximum height, hang time, horizontal range.

Answer 1

Start by getting time to the peak and then the height.
The initial vertical velocity is 29 sin (69) = v.
It loses velocity due to the acceleration of gravity at a rate of g=-9.8 m/s^2,
so it will stop rising when v - (9.8) t = 0. The height will be h = vt - (1/2) g t^2.

It has a horizontal velocity of u = 29 cos(69), and it will travel for a period of 2t [t up and then t on the way down), covering a distance of 2 u t. The details are up to you.